(1/3)^2u+5=(1/9)^3u-1

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Solution for (1/3)^2u+5=(1/9)^3u-1 equation: 



(1/3)^2u+5=(1/9)^3u-1

We move all terms to the left:

(1/3)^2u+5-((1/9)^3u-1)=0



Domain of the equation: 3)^2u!=0

u!=0/1

u!=0

u∈R





Domain of the equation: 9)^3u-1)!=0

u!=0/1

u!=0

u∈R



We add all the numbers together, and all the variables

(+1/3)^2u-((+1/9)^3u-1)+5=0

We calculate fractions


9^3u/3^2u*9)^3u-1))+(-3^2u/3^2u*9)^3u-1))+5=0

We can not solve this equation

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